![]() ![]() Here is how we dealt with the problem in the third edition (published in January 2017) of MATLAB Guide. Moreover, it may not even save correctly if your editor is not set up for Unicode characters. However, there is a catch: the “×” symbol is a Unicode character, so it will not print correctly when you include the output in LaTeX (at least with the version provided in TeX Live 2016). There are still remnants of “x”, for example in whos s for the example above, but I presume that all occurrences of “x” will be changed to the new symbol in the next release Second, the times symbol is no longer an “x” but is now a multiplication symbol: “×”. It does so for arrays of type other than double precision and char. First, MATLAB prints a header giving the type and size of the array. demodulation takes place, only 2 symbols received.At first sight, you might not spot anything unusual, other than the new string datatype.Rx filter receives only the last 2 symbols.Rx filter hardware starts, with a delay of 5 symbols, the first 5 symbols get lost.Tx filter hardware starts, with a delay of 5 symbols, the first 5 symbols get lost.simulation starts, 12 bits start transferring. ![]() I think that in the simulator, it assumes that both of the rx, tx filter's hardware set up at the same time, and while they do set themselves up, the transmission has already started, and the 10 bits just get lost due to that, in the below order: But all of the 12 data would be sent and received, right? The recevier (a second Adalm-Pluto) would have its recevier filter ready to receive data, so there would not be any loss in data, just the trasmitter's initial delay and the receiver's initial delay. Why do the 10 bits get lost due to the delay? In the real world, using a real device (say something like Adalm-pluto) to send 12 bits, wouldn't the all those bits be sent? The transmitter device would wait for the filter's hardware or software to set itself up, and then start sending the data. The result of the above is that I am sending 12 bits, the 10 of them get lost due to the delay of the filters, and I end up sending only 2 bits (the two first bits of the array), the demodAligned are the received and demodulated bits and the srcAligned are the source bits, before getting filtered, but 'aligned' to compensate for the delays of the rx/tx filters %Next, get the aligned bits from the received bit sequence by extracting all but the first 10 bits.ĭemodAligned = demodOut((delayInBits+1):end) SrcAligned = srcBits(1:(end-delayInBits)) ![]() %Align source bits (extracting all bits but the last 10 bits which is our total delay) %We need to know the delay in bits, not symbols:ĭelayInBits = delayInSymbols * bitsPerSymbol RxFiltOut = rxFilt(txFiltOut ) %pass the data to the receiver s filter.ĭemodOut = qamdemod(rxFiltOut,modOrder,"OutputType","bit","UnitAveragePower",true) %demodulate.ĭelayInSymbols = rxFilt.FilterSpanInSymbols/2 + txFilt.FilterSpanInSymbols/2 TxFiltOut = txFilt(modOut) %pass the modulated symbols throught the tx filter. ModOut = qammod(srcBits,modOrder,"InputType","bit","UnitAveragePower",true) %qam modulation of the bits to send SrcBits = randi(,numBits,1) %generate random bits to send RxFilt = comm.RaisedCosineReceiveFilter %make the receive filter Since comment symbols / and / are automatically assigned in the generated code, comments can be unintentionally nested and behave differently than expected. TxFilt = comm.RaisedCosineTransmitFilter %make the transmit filter ![]() C chart comments in generated code use multibyte character code. Can anyone please help me 0 Comments Sign in to comment. You can also include comments in generated code for an embedded target (see Model Configuration Parameters: Comments (Simulink Coder). 1 Link Commented: ztjona on Accepted Answer: Star Strider I want to use Greek symbol epsilon '' in my legend and I use \epsilon. In my minimal example I send 12 bits, with modulation order 2 ( so 1 bit = 1 symbol) to make it simple: numBits = 12 %send 12 bitsīitsPerSymbol = log2(modOrder) % modOrder = 2^bitsPerSymbol Use the symbols, //, and to represent comments as shown in these examples: // C++ comment line / C comment line /. Because of this filter both the receiver and the transmitter each have a delay of 5 symbols on the data transmission. Now, the comm.RaisedCosineTransmitFilter has a property FilterSpanInSymbols,so if the FilterSpanInSymbols = 10, then the delay of the tx/rx filters is 5. I am using the matlab online simulator and taking the course " Wireless communications Onramp" where I need to use a Raised Cosine Transmit Filter to filter the data both in the transmitter and the receiver. ![]()
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